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Leya [2.2K]
2 years ago
6

Help need it…please I need it now

Mathematics
1 answer:
tino4ka555 [31]2 years ago
4 0

Answer:

Here is the solution . see the attached file

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For what value of x does (x + 3)^2-5=0
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Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

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