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4 years ago

For what value of x does (x + 3)^2-5=0

Mathematics

1 answer:

ArbitrLikvidat [17]4 years ago

7 0

Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

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A point is chosen at random on AK what is the probability that one point will be on BG?

kobusy [5.1K]

Answer:

11/21.

BG has a total of 11 points (when you include 0), and there are 21 points total. 11/21 cannot be simplified, your final answer is 11/21.

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3 years ago

Grace and Zoe like to jump rope grades jump 66 times a minute Zoe jumps 56 times a minute they both Count Their jumps today and

san4es73 [151]

Answer:

Grace jumps for 9 minutes.

Zoe jumps for 12 minutes.

Step-by-step explanation:

Let the time for which Grace jumps the rope = $x$ minutes

Let the time for which Zoe jumps the rope = $y$ minutes

As per question statement:

$x+y=21 ..... (1)$

Number of times Grace jumps in one minute = 66

Number of times Zoe jumps in one minute = 56

Number of times Grace jumps in $x$ minutes = 66

Number of times Zoe jumps in $y$ minutes = 56

As per question statement:

$66x+56y=1266 ...... (2)$

Multiplying equation (1) with 66 and subtracting equation (2) from it:

$10y = 1386 - 1266\\\Rightarrow 10y=120\\\Rightarrow y =\bold{12\ min}$

By equation (1):

$x=21-12=\bold{9\ min}$

Therefore, the answer is:

Grace jumps for 9 minutes.

Zoe jumps for 12 minutes.

5 0

3 years ago

John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid

tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

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