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egoroff_w [7]
3 years ago
11

Anyone here good at Math, if you are please answer these two questions.

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0

Num 1: y= 3/2 x - 6

Num 2: y= -4/7 x - 2

Hope this helps

alukav5142 [94]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

The equation to the graph is B y=3/2x-6.

The equation that is equivalent to the original is A y=4/7x+2.

-hope it helps

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A battery with a voltage of 3 V provides a voltage of 0.56 C to some circuits. Calculate the electrical power provided by this b
Assoli18 [71]

Answer:

The power is 1.68 W.

Step-by-step explanation:

Voltage, V = 3 V

charge, q = 0.56 C

time, t = 1 s

The power is given by

P = V q/t

P = 3 x 0.56 / 1

P = 1.68 W

6 0
3 years ago
ANSWER ASAP! 25 POINTS! WILL GIVE BRAINLIEST!
aleksklad [387]

Answer:

16(x^{2})

Step-by-step explanation:

we know that

(4x)^{2} =(4^{2})(x^{2})=16(x^{2})

therefore

The expression in the form k(x^{n}) is equal to

k(x^{n})=16(x^{2})

where

k=16

n=2

4 0
3 years ago
What’s the answer to this question below. A b c or d
tigry1 [53]

Answer:

option C

x = 2 , x = -5

Step-by-step explanation:

You have to remember the "Quotient Rule" for exponent having same base.

The quotient rule tells us that we can divide two powers with the same base by subtracting the exponents.

Here,

base = 12

exponents = (x² + 5x - 4) , (2x + 6)

12^(x² + 5x - 4)  = 12^(2x + 6)

12^((x² + 5x - 4) /(2x + 6)) = 1

12^((x² + 5x - 4) -(2x + 6)) = 1

12^(x² + 5x - 4 - 2x - 6) = 1

12^(x² + 5x - 2x - 4 - 6) = 1

12^(x² + 3x - 10) = 1

ln (12^(x² + 3x - 10)) = ln(1)

(x² + 3x - 10)ln(12) = 0

ln(12) = 0 rejected

x² + 3x - 10 = 0

Now solve the quadratic equations by factorisation.

(x-2)(x+5) = 0

x = 2 , x = -5

5 0
4 years ago
Read 2 more answers
The oil prices for 2014, rounded to the nearest dollar, were: 95, 101, 101, 102, 102, 106, 104, 97, 93, 84, 76, 59. what is the
kipiarov [429]
  • Interquartile Range (IQR) = Q_3-Q_1 , with Q_3 as the upper quartile and Q_1 as the lower quartile.

Firstly, rearrange the data so that it's in ascending order: \{59,76,84,93,95,97,101,101,102,102,104,106\}

Next, find the median:

\{59,76,84,93,95,\boxed{97,101,}101,102,102,104,106\}\\\\\frac{97+101}{2}\\\\\frac{198}{2}\\\\99

Now to find the lower quartile, find the "median" of the data set that's to the left of 99:

\{\overbrace{59,76,84,93,95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\{\overbrace{59,76,\boxed{84,93}95,97}^{\textsf{to the left of the median}},101,101,102,102,104,106\}\\\\\frac{84+93}{2}\\\\\frac{177}{2}\\\\88.5

Now to find the upper quartile, it's the similar process as finding the lower quartile, except that you are finding the "median" of the data set to the right of 99:

\{59,76,84,93,95,97,\overbrace{101,101,102,102,104,106}^{\textsf{to the right of the median}}\}\\\\\{59,76,84,93,95,97,\overbrace{101,101,\boxed{102,102} 104,106}^{\textsf{to the right of the median}}\}\\\\\frac{102+102}{2}\\\\\frac{204}{2}\\\\102

Now that we have the upper and lower quartile, subtract them:

102-88.5=13.5

<u>In short, the IQR of this data set is 13.5.</u>

8 0
3 years ago
Hey Everyone I was asking anyone can help with this problem it would really appreciated.
posledela

Answer:

angle G = angle I

HGI=HIJ by RHS fact

HGI=HIJ corresponding angles are alwyas congurrent

6 0
3 years ago
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