All categories

3 years ago

It’s timed need help ASAP!!

Mathematics

2 answers:

Charra [1.4K]3 years ago

8 0

If u measure it I think you’ll get the answer because they look pretty similar

gtnhenbr [62]3 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

HELPP PLSSMFCODSM MATH TEST !

tresset_1 [31]

Answer:

17= addition

18 = 27

Let's solve your equation step-by-step.

43x−4=5−x

Step 1: Simplify both sides of the equation.

43x−4=5−x

43x+−4=5+−x

43x−4=−x+5

Step 2: Add x to both sides.

43x−4+x=−x+5+x

73x−4=5

Step 3: Add 4 to both sides.

73x−4+4=5+4

73x=9

Step 4: Multiply both sides by 3/7.

(37)*(73x)=(37)*(9)

x=277

Answer:

x=277

6 0

3 years ago

The seed and skin of a typical avocado is about 30% – 40% of the avocados weight for an eight- ounce avocado how many ounces of

MariettaO [177]

Answer:

4.8 oz

Step-by-step explanation:

if 30-40 of the avocados weight is seed and skin that subtracted from 100% is the amount of edible fruit.

about 60% is edible fruit

multiply that by 8 ounces to get the amount of edible fruit

8 x 0.6 = about 4.8 ounces of edible fruit

3 0

3 years ago

Select the correct answer. At a walk-in interview, 12% of candidates can be selected, and 28% of candidates can be put on hold f

Troyanec [42]

Answer: A 45

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

Therefore, there's 28% probability that every student in the group is a girl.

5 0

3 years ago

Need help on this please

rodikova [14]

Answer:

The answer should be 113.04

6 0

3 years ago

Read 2 more answers