Question

Pleaseee help, Solve for x and y :3

Answer 1

Answer:

x = $\sqrt{6}$ , y = 2$\sqrt{3}$

Step-by-step explanation:

using the tangent ratio and the exact value tan45° = 1 , then

tan45° = $\frac{opposite}{adjacent}$ = $\frac{x}{\sqrt{6} }$ = 1 , then

x = $\sqrt{6}$

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using the cosine ratio in the right triangle and the exact value

cos45° = $\frac{1}{\sqrt{2} }$ , then

cos45° = $\frac{adjacent}{hypotenuse}$ = $\frac{\sqrt{6} }{y}$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

y = $\sqrt{6}$ × $\sqrt{2}$ = $\sqrt{12}$ = 2$\sqrt{3}$