Answer:
For ![\[20\]](https://tex.z-dn.net/?f=%5C%5B20%5C%5D)
minutes Elena add water to correct the error.
Step-by-step explanation:
The capacity of the washing machine is gallons.
She uses gram soap for ![\[10\]](https://tex.z-dn.net/?f=%5C%5B10%5C%5D)
gallon of water
Her son by mistake dissolved ![\[60\]](https://tex.z-dn.net/?f=%5C%5B60%5C%5D)
grams of soap to gallons of water.
![\[60\]-](https://tex.z-dn.net/?f=%5C%5B60%5C%5D-)
gram soap is right for ![\[30\]](https://tex.z-dn.net/?f=%5C%5B30%5C%5D)
gallons of water, thus gallon of water must be added more.
She pore water ![\[2\]](https://tex.z-dn.net/?f=%5C%5B2%5C%5D)
gallons per minute thus, gallons of water will takeminutes.
Learn more about equations : brainly.com/question/20727602?referrer=searchResults
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2
Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2 = x^2 -4x + 4
2(x-2)^2 = 2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8
Now that 2(x-2)^2 is done lets move on to 3(x-2).
Use the distributive property and distribute the 3
3(x-2) = 3x - 6
All that is left is the -2
Now lets put it all together
2(x-2)^2 + 3(x-2)-2
2x^2 - 8x + 8 + 3x - 6 - 2
Now combine all our like terms
2x^2 - 8x + 8 + 3x - 6 - 2
Combine: 2x^2 = 2x^2
Combine: -8x + 3x = -5x
Combine: 8 - 6 - 2 = 0
So all we have left is
2x^2 - 5x
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer:
The one that ends with jointly!
Step-by-step explanation:
0.83 can also be written as 83/100, so the numerator will be 83.
