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katrin [286]
2 years ago
7

Can teachers see what my kids did wrong on IMC online?

Mathematics
1 answer:
hjlf2 years ago
3 0

Answer:

Teachers activate a session at the beginning of a synchronous remote class. Then, they can see thumbnails of each student's screen, review the tabs they have open, and scan the web address of the websites they've visited.

Step-by-step explanation:

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Expand and combine like terms. (7b^5-4b)(7b^5+4b)=
adoni [48]

Answer:

49b^10 -16b^2

Step-by-step explanation:

(7b^5)^2 -(4b)^2=

49b^10 - (4b)^2=

49b^10 - 16b^2

7 0
3 years ago
Solve for -3x ≤ -9<br> I need it for math so be correct
ohaa [14]

Divide each term by −3-3 and simplify.

Inequality Form:

x≥3

8 0
3 years ago
Read 2 more answers
Which of the following equations is equivalent to the formula for velocity
bazaltina [42]
Where are the answer choices?

but the answer either way has to be:
v = d/t . v is velocity, d is for distance, and t is for time
6 0
1 year ago
Parts being manufactured at a plant are supposed to weigh 65 grams. Suppose the distribution of weights has a Normal distributio
andrew-mc [135]

Answer:

0.64%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 75 grams and a standard deviation of 22 grams.

This means that \mu = 75, \sigma = 22

Sample of 144:

This means that n = 144, s = \frac{22}{\sqrt{144}} = 1.8333

More than 80 or less than 70:

Both are the same distance from the mean, so we find one probability and multiply by 2.

The probability that it is less than 70 is the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{70 - 75}{1.8333}

Z = -2.73

Z = -2.73 has a pvalue of 0.0032

2*0.0032 = 0.0064.

0.0064*100% = 0.64%

The probability is 0.64%.

3 0
3 years ago
Is 16-7=4+5 true, false, or open?
jek_recluse [69]

Answer:

open

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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