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3 years ago

Divide: 6 ÷ 1

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

6 0

One sixth times start fraction 2 over 1 is end fraction

fredd [130]3 years ago

5 0

Answer:

One-sixth times StartFraction 2 over 1 EndFraction

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Lorreen sells 18 adult tickets, 23 student tickets, and 10 discount tickets for the school play. Write the ratio student tickets

Slav-nsk [51]

Answer:

23:18,23 to 18,23/18

Step-by-step explanation:

the three ways to write a ratio are colon,the word to, and the divide symbol .

7 0

2 years ago

Denver, Engle and Fido are all dogs who eat differing amounts of dog food.

alekssr [168]

Answer:

25%

Step-by-step explanation:

If Denver gets 8/19 of the food, 11/19 of the food is left between Engle and Fido.

If the food is shared in a ratio of 6 : 2 between the pair, Engle gets 6/8 and Fido gets 2/8.

Thus, 2/8 = 25%.

3 0

3 years ago

Read 2 more answers

(-7.5) + (-5.3) (-1.9)

Lisa [10]

Answer:

2.57

Step-by-step explanation:

You first have to multiply the -5.3 times the -1.9. Once you do that, you get 10.07. Then, you add the -7.5.

Here are the equation steps:

(-7.5) + (-5.3)x(-1.9)

(-7.5) + (10.07)

2.57

6 0

3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago

On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to

Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = $(21-11) \ million$ = 10 million

1960-1970 = $(41-21)\ million$ = 20 million

1970-1980 = $(71-41)\ million$ = 30 million

1980-2000 = $(161-71)\ million= 90$ million

Rate of change (1950-1960)= $\frac{10}{11} \times 100= 90.90\%$

Rate of change (1960-1970) = $\frac{20}{21} \times 100= 95.23\%$

Rate of change (1970-1980)= $\frac{30}{41} \times 100= 73.17\%$

Rate of change (1980-2000)= $\frac{90}{71} \times 100= 126.76\%$

∴ rate of change between 1980 to 2000 is 126.78%

7 0

3 years ago