Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Answer:
3
Step-by-step explanation:
Answer:
GH= 47
Step-by-step explanation:
~
Answer:
Step-by-step explanation:
using the 30- 60- 90 triangle for exact values , then
tan60° = 
, and
cot60° = 
= 
cos60° = 
cot60° cos60°
= ×
= 
← rationalise the denominator by multiplying by 
= ×
=
