The numbers in the sequence will be 40, 80, and 160.
<h3>How to get the values?</h3>
Let x be the first number in the sequence, so the first three numbers are {x, 0.5x, 0.5²x}.
Then
{x/4 + 10, 0.5x - 10, 2(0.5²x) + 10}
0.5x - 10 = x/4 + 10 + c = x/2 - 10 = x/4 + 10 + c
2(0.5²x) + 10 = 0.5x - 10 + c = x/2 + 10 = x/2 - 10 + c
Solve the second equation for c :
x/2 + 10 = x/2 - 10 + c
c = 20
Substitute this into the first equation and solve for x :
x/2 - 10 = x/4 + 10 + 20
x/4 = 40
x = 160
Then the terms are {160, 80, 40}
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You would set it up: .5/100 = x/490 and then cross multiply .5 time 490 and 100 times x, and end up with: 245=100x. divide by 100, and get 2.45
Answer:
^62 with a numertor of 66 you divide by .21
Step-by-step explanation:
Answer:
X=5
Step-by-step explanation:
