Question

What is the next term of the geometric sequence? -128/27,32/9,-8/3

Answer 1

Answer:

2

Step-by-step explanation:

a1 = -128/27

a2 = 32/9

a3 = -8/3

Therefore, a = a1 = -128/27

r = a3 ÷ a2 = -8/3 ÷ 32/9 = -3/4

So $a_n=ar^{n-1}=-\frac{128}{27} (-\frac{3}{4})^{n-1}$

Therefore, a4 = (-128/27) x (-3/4)^(4-1)

= (-128/27) x (-3/4)^3

= (-128/27) x (-27/64)

= 2