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2 years ago

What is the next term of the geometric sequence? -128/27,32/9,-8/3

Mathematics

1 answer:

IrinaVladis [17]2 years ago

3 0

Answer:

Step-by-step explanation:

a1 = -128/27

a2 = 32/9

a3 = -8/3

Therefore, a = a1 = -128/27

r = a3 ÷ a2 = -8/3 ÷ 32/9 = -3/4

So $a_n=ar^{n-1}=-\frac{128}{27} (-\frac{3}{4})^{n-1}$

Therefore, a4 = (-128/27) x (-3/4)^(4-1)

= (-128/27) x (-3/4)^3

= (-128/27) x (-27/64)

= 2

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The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .

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Answer:

$32,24,18,\frac{27}{2} ,\frac{81}{8}$

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is $32,x,y,z,\frac{81}{8}$

Recall that term of a geometric sequence are generally in the form:

$a,ar,ar^2,ar^3,ar^4$

This implies that:

a=32 and $ar^4=\frac{81}{8}$

Substitute a=32 and solve for r.

$32r^3=\frac{81}{8}$

$r^4=\frac{81}{256}$

Take the fourth root to get:

$r=\sqrt[4]{\frac{81}{256} }$

$r=\frac{3}{4}$

Therefore $x=32*\frac{3}{4} =24$

$y=24*\frac{3}{4} =18$

$z=18*\frac{3}{4} =\frac{27}{2}$

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