All categories

3 years ago

A store sells grapes for $1.99 per pound. You buy 2.34 lbs. of grapes. How much do you pay? Please help!

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

7 0

2.34 lbs at 1.99 per lb..

2.34 * 1.99 = 4.6566 rounds to 4.66 <=

melisa1 [442]3 years ago

6 0

4.6566 would be the exact answer but since it’s money write Down 4.65

You might be interested in

A player plays a game in which, during each round, he has a probability 0.55 of winning $1 and probability 0.45 of losing $1. Th

Artemon [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

$10 per pound of deli meat 3 1/2 pounds.

PSYCHO15rus [73]

The meat would end up costing $35 because you want to multiply $10*3\frac{1}{2}=35$

4 0

3 years ago

Read 2 more answers

Write the standard form of the line that passes through (-1,-3) and (2,1).

kobusy [5.1K]

Answer:

Step-by-step explanation:

$\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\$

$\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\$

Convert equation to standard form

$y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5$

5 0

3 years ago

Write an expression for the description: the product of 3 and p subtracted from 6

Shalnov [3]

Answer:

6 - 3p

Step-by-step explanation:

The word "product" indicates to multiply 3 and p, and "subtracted from" tells us to use subtraction.

4 0

3 years ago

Read 2 more answers

Write down in terms of n, an expression for the nth term

Scilla [17]

Answer:

${ \bf{(a).}} \\ { \tt{ {n}^{th} = a + (n - 1)d }} \\ { \tt{ {n}^{th} = 6 + (n - 1) \times - 4 }} \\ {n}^{th} = 10 - 4n \\ \\ { \bf{(b).}} \\ { \tt{ {n}^{th} = - 8 + (n- 1) \times - 7 }} \\ { \tt{ {n}^{th} = -1 - 7n}}$

3 0

2 years ago