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Natasha2012 [34]
2 years ago
15

The temperature is 20 degrees below zero. What numerical value represents the temperature?

Mathematics
1 answer:
luda_lava [24]2 years ago
8 0

Answer:

-20

Step-by-step explanation:

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Choose the missing step in the given solution to the inequality -x -10 &gt; 14 + 2x <br>​
Andreyy89

Answer:

x < -8

Step-by-step explanation:

-x - 10 > 14 + 2x

Subtract 2x from both sides;

-3x - 10 > 14

Add 10 to both sides;

-3x > 24

Divide both sides by -3

The sign switches when divide by a negative number.

x < -8

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What is the volume of the prism that can be constructed from this net?<br><br><br> units3
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Write the decimal number in words 235.678
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Two hundred thirty-five and six hundred seventy-eight thousandths
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3 years ago
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(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi
Drupady [299]

Answer:

a. \dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. x(t) = 6\frac{2}{3} \cdot c \cdot t

c. c  = \dfrac{3}{8}  \ g/L

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx =  (5·c - 5·c/3)×dt = 20/3·c = 6\frac{2}{3} \cdot c \cdot dt

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. The amount of salt, x after t minutes is given by the relation

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

dx = 6\frac{2}{3} \cdot c \cdot dt

x(t) = \int\limits \, dx  = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt

x(t) = 6\frac{2}{3} \cdot c \cdot t

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10

6\frac{2}{3} \times c  =\dfrac{25 \ grams }{10}

c  =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} }  = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200}  \ g/L = \dfrac{3}{8}  \ g/L

c  = \dfrac{3}{8}  \ g/L

4 0
2 years ago
A student estimates the weight of astronauts on the moon by multiplying their weight by the decimal 0.16666....what fraction can
Elden [556K]

Let x = 1.66666... ....(1)

Multiply both sides of equation (1) by 10.

10x = 1.666666.... .... (2)

Multiply both sides of equation (1) by 100.

100x = 16.66666....... (3)

Subtract equation (2) from equation (3)

100x - 10x = 16.66666...- 1.66666...

90x = 15

x= \frac{15}{90}  = \frac{1}{6}

Hence, the required fraction form is \frac{1}{6} .... Answer.


3 0
2 years ago
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