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2 years ago

The temperature is 20 degrees below zero. What numerical value represents the temperature?

Mathematics

1 answer:

luda_lava [24]2 years ago

8 0

Answer:

-20

Step-by-step explanation:

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6) The sum of three consecutive numbers is seventy-eight.

tia_tia [17]

Answer:

Step-by-step explanation:

In my opinion the three consecutive numbers should be 25 26 and 27

25 + 26 + 27 = 78

3 0

3 years ago

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Two equations are shown in the picture please answer. giving brainiest

Dvinal [7]

Answer:well for the first one I am not sure but I think that since four is over the x there should be 4/x + 3 so tragically I don’t know the answer but I think it should be 12 the x should be 12 because 4x3=12 so yea 12

Step-by-step explanation:and for the other one I don’t know but ima try it should be two because 2x2=4 and so y=1-2x2-4 that’s what I think sorry. I got it wrong and do good on your test for me please

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3 years ago

Pablo borrowed $900 from a credit union for 3years and was charged simple interest at a rate of 3%. What is the amount of intere

tensa zangetsu [6.8K]

Answer:81

Step-by-step explanation:

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3 years ago

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Find the equation of the straight line<br> that passes through (5, 6) and (5, −6).

GalinKa [24]

9514 1404 393

Answer:

x = 5

Step-by-step explanation:

These points have the same x-coordinate, so are on the same vertical line:

x = 5

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3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago