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2 years ago

3 over 7 = − 1 over 7 q

1 answer:

6 0

Q= - 1/3 is the answer-move the negative sign to the left multiply both sides by 7q then cancel 7 then finally divide both sides by 3. Hope this helps

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I am so confused plz halp

lyudmila [28]

Step-by-step explanation:

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2 years ago

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What is the greatest possible error of the measurement?

dezoksy [38]

I think it would be A. 9.6. I'm completely sure on that one.

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2 years ago

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Simplify:9-1÷2÷27^2÷3

sammy [17]

First let's calculate the exponents.

$27^2 : 729 = 9-1\div \:2\div \:729\div \:3$

Now we should multiply and divide.

$1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}$

Now we should add and subtract.

$9-\frac{1}{4374} :\frac{39365}{4374} = \frac{39365}{4374}$

Convert the improper fractions into mixed numbers.

$8\frac{4373}{4374}$

Answer :

$8\frac{4373}{4374}$

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2 years ago

What is y 12y - 19= 6y+1=

nadezda [96]

Answer:

Step-by-step explanation:

12y-19= 6y+1

12y-6y = 1 +19

6y = 20

y = 20/6

y= 10/3 or 3.33..

<h2>HAVE A NICE TIME :)</h2><h2>pls give a brainliest if it is CORRECT</h2>

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1 year ago

Problem PageQuestion Working together, two pumps can drain a certain pool in hours. If it takes the older pump hours to drain th

gizmo_the_mogwai [7]

Answer:

10.5 hours.

Step-by-step explanation:

Please consider the complete question.

Working together, two pumps can drain a certain pool in 6 hours. If it takes the older pump 14 hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own?

Let t represent time taken by newer pump in hours to drain the pool on its own.

So part of pool drained by newer pump in one hour would be $\frac{1}{t}$ .

We have been given that it takes the older pump 14 hours to drain the pool by itself, so part of pool drained by older pump in one hour would be $\frac{1}{14}$ .