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Agata [3.3K]
3 years ago
5

3 over 7 = − 1 over 7 q

Mathematics
1 answer:
Finger [1]3 years ago
6 0
Q= - 1/3 is the answer-move the negative sign to the left multiply both sides by 7q then cancel 7 then finally divide both sides by 3. Hope this helps
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67000 dollars is placed in an account with an annual interest rate of 8.25%. how much will be in the account after 28 years, to
anastassius [24]

Answer:

The Amount of money in the account after 28 years is $616,674.5

Step-by-step explanation:

Given as :

The principal amount placed in the account = p = $67,000

The rate of interest = r = 8.25%

The time period of amount in the account = t = 28

Let the Amount of money in the account = $A

Now<u>, From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $67,000 × (1+\dfrac{\textrm 8.25}{100})^{\textrm 28}

Or, A = $67,000 × (1.0825)^{28}

Or, A = $67,000 × 9.2041

∴ A = $616,674.7

So, The Amount of money in the account = A = $616,674.5

Hence, The Amount of money in the account after 28 years is $616,674.5  Answer

5 0
3 years ago
Which of the following is a geometric sequence
mel-nik [20]
B.) 2,4,8,16,32 is the geometric series as the common ratio is equal for each step
3 0
3 years ago
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In which step did John first make a mistake?<br> look at photos
Verizon [17]

Answer:

John did not make a mistake

Step-by-step explanation:

he did everything correct

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3 years ago
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Find the next two terms for the following pattern 1, -2, 2, -4, 0
Oxana [17]
After figuring out a common difference in this pattern, we can get further terms in the pattern:
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5 0
3 years ago
Write the first 6 terms of the arithmetic sequence whose first term is 8 and has a common difference of 2
soldier1979 [14.2K]

Answer: The first 6 terms are = 8, 10, 12,14,16,18

Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

where a1 = First term  given as 8 and

d=  common difference given as 2

Therefore  We have that

the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

a1= 8

second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

= 8+ 2(1) = 10

3rd term

an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2

= 8+ 2(2)= 8 + 4=12

4th term

an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2

= 8+ 2(3)= 8+6=14

5th term

an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2

= 8+ 2(4)=8+ 8=16

6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

= 8+ 2(5)=8 +10 =18

6 0
3 years ago
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