3 over 7 = − 1 over 7 q

the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function

Likurg_2 [28]

The function of the area of the square is A(t)=121 $t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square= $(length of side)^{2}$

Area of square= $(11t)^{2}$ {as the length of side is 11t}{varies by time}

Area of square=121 $t^{2}$

Therefore,The function of the area of the square is A(t)=121 $t^{2}$

Learn more about The function of the area of the square is A(t)=121 $t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square= $(length of side)^{2}$

Area of square= $(11t)^{2}$ {as the length of side is 11t}{varies by time}

Area of square=121 $t^{2}$

Therefore,The function of the area of the square is A(t)=121 $t^{2}$

Learn more about area here:

brainly.com/question/27683633

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3 0

2 years ago

How many solutions does the system of equations below have?<br> y = −6x + 9<br> y = 9/8x − 3

torisob [31]

Answer:

1 solution

Step-by-step explanation:

A system of two equations can be classified as follows:

1) If the slopes are the same but the y-intercepts are different, the system has no solution.

<em>2) If the slopes are different, the system has one solution.</em>

3) If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions

Hope this helps you

4 0

3 years ago

What is the sum of the interior angles of the polygon shown below

DanielleElmas [232]

Answer:

720 degrees.

Step-by-step explanation:

The sum of the interior angles of a convex polygon with n sides is

180(n - 2) degrees.

In this case, n = 6 sides, so the angle sum is

180(6 - 2) = 180(4) = 720 degrees.

The reason this works is that if you draw a diagonal from one vertex to the others (see attached image), you get 2 fewer triangles than the number of sides. Each triangle contains a total of 180 degrees, so the total of all the interior angles is 180(n - 2).