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Rudiy27
3 years ago
8

Ana bought 114 inches of trim. She wanted to cut it into pieces that were 6 inches long. How many pieces of trim will Ana have?

Mathematics
2 answers:
otez555 [7]3 years ago
6 0
So she bought 114 inches of trim
She wants to cut the pieces into 6 inches
114/6=19
artcher [175]3 years ago
5 0
6 inches = 1 piece
114 inches = 114 ÷ 6 = 19 pieces
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Cheese sticks that were priced at "10 for 1 dollar are now "4 for 1 Dollar. Find each percent change. Find the percent increase
lina2011 [118]
Cheese sticks were 10. for dollar or 10 cents a piece (10/100 =.10 or 10 cents. now 4 for dollar or ,25 x 100 = 25 cents each (4/100). percent change

.25 - , 10 =.15
,15/,25 = .60
.60 x 100 = 60%
6 0
4 years ago
Camilla bought a book that was on sale for 25% off the retail price. The retail price of the book was $12. What was the price Ca
Nonamiya [84]

Answer:

The price that Camilla paid for the book was $9.

Step-by-step explanation:

To be able to find the pice that Camilla paid for the book, first, you have to calculate the 25% of the price of the book:

$12*25%=$3

Now, you have to subtract that amount from the price of the book:

$12-$3=$9

According to this, the answer is that the price that Camilla paid for the book was $9.

6 0
3 years ago
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vova2212 [387]

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Step-by-step explanation:

4 0
3 years ago
How to write three hundred thousand, five thousand sixty three in standard form
anygoal [31]
300,000 <-- three hundred thousand

5,000 <-- five thousand

63 <-- sixty three

300,000
    5,000
         63

305,063

305,063 is your answer.

Hope this helps.

3 0
3 years ago
Read 2 more answers
Chicken Delight claims that 87% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 80 or
jeka57 [31]

Answer:

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

Step-by-step explanation:

In this question we have to test an hypothesis.

The null and alternative hypothesis are:

H_0: \pi\geq0.87\\\\H_a:\pi

The significance level is assumed to be 0.01.

The sample of size n=80 gives a proportion of p=61/80=0.7625.

The standard deviation is:

\sigma=\sqrt{\frac{\pi(1-\pi)}{N} }=\sqrt{\frac{0.87*0.13}{80} }=0.0376

The statistic z is then

z=\frac{p-\pi+0.5/N}{\sigma}=\frac{0.7625-0.87+0.5/80}{0.0376} } =\frac{-10125}{0.0376} =-2.70

The P-value is

P(z

The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

6 0
3 years ago
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