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3 years ago

Ana bought 114 inches of trim. She wanted to cut it into pieces that were 6 inches long. How many pieces of trim will Ana have?

Mathematics

2 answers:

otez555 [7]3 years ago

6 0

So she bought 114 inches of trim
She wants to cut the pieces into 6 inches
114/6=19

artcher [175]3 years ago

5 0

6 inches = 1 piece
114 inches = 114 ÷ 6 = 19 pieces

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A basketball player has already scored 56 points in a game. The team record for points in a game is 72. Which equation would all

maks197457 [2]

A because if you subtract 56 from both sides, then x would show you what equals the tied record

8 0

2 years ago

Solve the inequality 3(y+5)>21

Kaylis [27]

Answer:

y > 2

Step-by-step explanation:

1) $3(y+5)>21$

Divide both sides by 3.

2) $y+5>7$

Move the constant to the right side and change it's sign.

3) $y>7-5$

Subtract the numbers.

4) $y>2$

8 0

2 years ago

Ashley charges $6 for a bracelet and 12$ for a necklace. She earned $168. Use b for bracelets and n for necklaces, and write an

yarga [219]

Answer:

Step-by-step explanation:

let the number of bracelet be b

Let the number of necklace be n

If Ashley charges $6 for a bracelet , the total amount charged for b bracelets will be 6b

If she charge $12 for a necklace, the total amount for n necklace will be 12n

If she earned $168 in total, then:

6b + 12n = 168

Divide through by 6

b + 2n = 28

Hence the equation for this situation is b + 2n = 28

Next is to solve for b:

Make b the subject of the formula:

b + 2n = 28

subtract 2n from both sides

b + 2n - 2n = 28 - 2n

b = 28 -2n

Hence the function for b will be b = 28-2n

8 0

2 years ago

M+2/3=1/4m-1 what the formula used to find the value of m?

zimovet [89]

Answer:

The value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

Solution:

Given, expression is $m+\frac{2}{3}=\frac{1}{4 m}-1$

Now, we have to solve the above given expression.

$\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1$

By multiplying the equation with m, we get

$\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}$

$\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}$

Now, let us use quadratic formula

$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in our problem, a = 12, b = 20, c = -3

$\begin{array}{l}{m=\frac{-20 \pm \sqrt{20^{2}-4 \times 12 \times(-3)}}{2 \times 12}} \\\\ {=\frac{-20 \pm \sqrt{400+144}}{24}} \\\\ {=\frac{-20 \pm \sqrt{544}}{24}} \\\\ {=\frac{-20 \pm 4 \sqrt{34}}{24}=\frac{-5 \pm \sqrt{34}}{6}} \\\\ {=\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}}\end{array}$

Hence the value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

7 0

3 years ago

Help pls

babymother [125]

Answer:

1). x = 10 m

2). x = 15 cm

3). x = 5 yd

4). AB = 10 units

Step-by-step explanation:

1). By Pythagoras theorem in the given triangle,

a² + b² = c²

Where 'c' = Hypotenuse

a and b = Legs of the right triangle

By substituting measures of the sides in the formula,

x² = 8² + 6²

x = $\sqrt{100}$

x = 10 m

2). By using Pythagoras theorem in this triangle,

x² = 9² + (12)²

x² = 81 + 144

x = $\sqrt{225}$

x = 15 cm

3). By Pythagoras theorem,

(13)² = x² + (12)²

169 = x² + 144

169 - 144 = x²

25 = x²

x = 5 yd

4). If BD is a perpendicular bisector of AC,

AD = CD = 6 cm

By Pythagoras theorem in ΔABD,

AB² = BD² + AD²

AB² = 8² + 6²

AB = $\sqrt{100}$

AB = 10 units

4 0

2 years ago

Read 2 more answers