Question

Please help me asap!

Answer 1

Answer:

$-3+2\sqrt{2}$

Step-by-step explanation:

$\frac{\sqrt{3} -\sqrt{6}}{\sqrt{3} +\sqrt{6}}$

$=\frac{(\sqrt{3} -\sqrt{6})(\sqrt{3} -\sqrt{6})}{(\sqrt{3} +\sqrt{6})(\sqrt{3} -\sqrt{6})}$

$=\frac{9-6\sqrt{2} }{-3}$

$=\frac{3(3-2\sqrt{2} )}{-3}$

$=-(3-2\sqrt{2})$

$=-3+2\sqrt{2}$