Question

Which diagram could be used to prove △ABC ~ △DEC using similarity transformations?

Answer 1

The answer is A just took the test.

Answer 2

Answer:

Step-by-step explanation:

(A) From the given figure, ∠BAC=∠CDE and ∠ACB=∠DCE=90°.

Thus, from ΔABC and ΔDEF, we have

∠BAC=∠CDE (Given)

∠ACB=∠DCE=90°

Thus, by AA similarity rule,

ΔABC is similar to ΔDEF.

Therefore, this option is correct.

(B) From the given figure, ∠ABC=∠DCE and ∠ACB=∠DEC

But, there is no angle and side is similar to the other angle or side of the triangle. Thus, this option is not correct.

(C) From the given figure, ∠ABC=∠ACB and ∠DCE=∠DEC

But, there is no angle or side is similar to the other angle or side of the triangle. Thus, this option is not correct.

(D) From the given figure, ∠BAC=∠CDE

But, there is no another angle or side is similar to the other angle or side of the triangle. Thus, this option is not correct.