Answer:
352cm²
Step-by-step explanation:
The shape is a cuboid and it has 6 faces, and the opposite faces are equal, so I calculate 3 different faces and multiplied it by 2 to give me the total surface area. Therefore, total surface area = the addition of all the surface areas in the shape. And to get each surface area, you have find the area of each of the 6 faces, and add them together, to give you the total surface area.
Answer:
A = 7,241.2454026112 square mm.
or exact : A = 2,304.96*π sq mm
Step-by-step explanation:
Cylinder formula: A = π* r^2 + 2 *π * r* h + π*r^2
is the surface area.
d = 2r = 39.2 mm
h = 39.2 mm
r = 19.6 mm
A = π* r^2 + 2 *π * r* h + π*r^2
A = 2* π* (19.6)^2 + 2π (19.6)*(39.2)
A = 2,413.748467537 + 4,827.496935
A = 7,241.2454026112 square mm.
or
A = 2*pi* (768.32 + 384.16)
A = 2*1,152.48* pi
A = 2,304.96*π sq mm
Answer:
a) F
b) B, E, D
Step-by-step explanation:
a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values
From the given option, the rate of change of the <em>y </em>to the<em> </em>x-values of B = the gradient = (4 units)/(2 units) = 2
The gradient of F = (-3units)/(1 unit) = -3
The gradient of A = 4/4 = 1
The gradient of C = -2/5
The gradient of D = 2/6 = 1/3
The gradient of E = 3/4
The segment with the greatest gradient is F
b) The steepest segment has the higher gradient
From their calculated we have;
The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3
Therefore, we have;
B, E, D.
Answer:
The Fringe of the rug is 754 cm.
Step-by-step explanation:
Given:
radius = 120 cm
We need to find the fringe of the outside rug.
Solution:
Since the rug is in the circular form.
We can say that fringe of the outside edge of the rug can be equal to circumference of the circle.
Then we will find the Circumference of the circle.
Circumference of the circle is given 2 times 'π' times radius 'r'.
framing in equation form we get;
Circumference of the circle = 
Circumference of the circle = 
Hence the Fringe of the rug is 754 cm.
