Question

Graph the function. f(x)=|x+2|-1

Answer 1

Answer:

a v-shaped graph with a minimum at (-2,-1) and x-intercepts at -1 and -3

Step-by-step explanation:

if you need to graph the function then start by creating an x-y table of values:

when x=0, y=1

so you the point: (0, 1)

when x=2, y=3

you have another point: (2,3)

when x=-2, y = -1

third point: (-2,-1)

when x=-3, y = 0

fourth point: (-3,0)

Answer 2

Graph is attached!!~

$\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}$

Graph details⤵️

$\blue{■} \sf \: f(x) = |x + 2| - 1$

$\sf \: Roots = (-3,0) (-1,0) \\ \sf \: \: Domain = x∈R \\ \sf \: Range = \: f(x)∈[-1,+∞⟩ \\ \sf \: Minimum =(-2 ,-1) \\ \sf \: Vertical \: intercept = (0,1)$