Answer: left one is no solution and right one is infinite solutions
explanation: the left one the lines don’t touch at all which has no solution and the right one means that both lines are on top of each other
The question is incomplete! Complete question along with answers and step by step explanation is provided below.
Question:
(a) Binomial probability distributions depend on the number of trials n of a binomial experiment and the probability of success p on each trial. Under what conditions is it appropriate to use a normal approximation to the binomial? (Select all that apply.)
nq > 10
np > 5
p > 0.5
np > 10
p < 0.5
nq > 5
(b) What is the probability of "12" or fewer successes for a binomial experiment with 20 trials. The probability of success on a single trial is 0.50. Use the normal approximation of the binomial distribution to answer this question. (Round your answer to four decimal places.)
Answer:
(a) The correct options are np > 5 and nq > 5
(b) P(x ≤ 12) = 0.8133
Step-by-step explanation:
Please refer to the attached images for explanation, I am unable to type in text editor due to some technical error!
Answer:
D is the correct answer
Step-by-step explanation:
Given:
Unit base price: $435
Credit Card interest rate, i = 9.4% compounded monthly; i = 0.00783/month comp monthly
n = 1.5 years = 18 months
sales tax = 8.51%
First, determine the actual price of the unit by adding the sales tax to the base price of the unit:
$435 * (1 + 0.0851)
Actual price = $472.0185
So, the total amount paid by Brian should be higher than the actual price since he used his credit card. Use the formula from economics:
F = P (1+i)^n
F = $507.96
Therefore, the total amount paid by Brian is $507.96.
(Hope this helps can I pls have brainlist (crown) ☺️)
Right answer number 3, think this gonna help u
Answer:
(27.3692 ; 44.6308)
Step-by-step explanation:
Mean, xbar = 36
Standard deviation, s = 11
Sample size, n = 12
Tcritical at 0.2, df = 12 - 1 = 11 ; Tcritical = 2.718
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/sqrt(n)
Margin of Error = 2.718 * 11/sqrt(12) = 8.6308
Confidence interval :
Lower boundary : 36 - 8.6308 = 27.3692
Upper boundary : 36 + 8.6308 = 44.6308
(27.3692 ; 44.6308)
