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borishaifa [10]
2 years ago
7

If Rachel can read 10 pages in 12 minutes how long does it take her to read 8 pages

Mathematics
1 answer:
juin [17]2 years ago
4 0

Answer:

9.6

Step-by-step explanation:

Step 1:

Find the rate of proportion

We can do 12/10 to find how many minutes it takes her to read 1 page, or 1.2.

Step 2:

Multiply 1.2 by 8 to get 9.6

<em>ALTERNATIVE METHOD:</em>

Divide 10 by 8 to get 1.25. Then divide 12 by 1.25 to get 9.6

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What is the slope of the line that passes through the points (-6, -8)(−6,−8) and (-14, 4) ?(−14,4)? Write your answer in simples
creativ13 [48]

Answer:

\huge\boxed{slope=-\dfrac{3}{2}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-6, -8) and (-14, 4).

Substitute

x_1=-6,\ y_1=-8,\ x_2=-14,\ y_2=4

m=\dfrac{4-(-8)}{-14-(-6)}=\dfrac{4+8}{-14+6}=\dfrac{12}{-8}=-\dfrac{12:4}{8:2}=-\dfrac{3}{2}

8 0
3 years ago
This is a long question so look at the picture thank<br> you
morpeh [17]

Answer:

2 students

Step-by-step explanation:

.............

4 0
3 years ago
Read 2 more answers
Harlon recorded this set of data, which contains an outlier. 163, 97, 184, 199, 169, 175 What is the range of this set of data?
maks197457 [2]
Hey there!

To find the range, first put the numbers in order from smallest to largest. 
97, 163, 169, 175, 184, 199

Then take the largest number, 199, and subtract the smallest number (in this case, the outlier) which is 97.

199-97=102

Thanks for using Brainly! Hope this helps :)


7 0
3 years ago
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X/4 +2 helppppp plzzz
inysia [295]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
How much Zn and how much HCl should be used to produce 1.5 g ZnCl2
tatuchka [14]

Answer:

  • 0.71963 g of Zn
  • 0.80256 g of HCl

Step-by-step explanation:

The required mass of reactants can be computed from the number of moles of product.

  moles of ZnCl₂ = (1.5 g)/(136.282 g) ≈ 0.0110066 moles

Then the mass of Zn required is ...

  mass of Zn = (0.0110066 mol)(65.382 g/mol) = 0.71963 g

Two moles of HCl are used in the reaction with each mole of Zn, so the mass of HCl required is ...

  mass of HCl = 2(0.0110066 mol)(36.458 g/mol) = 0.80256 g

_____

<em>Comment</em>

The discrepancy in the last two decimal places of the weights above versus the calculator output below comes from rounding of moles of Zn to 4 significant digits, instead of 5 or more. The number of moles of ZnCl₂ is closer to 0.0110066.

4 0
3 years ago
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