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o-na [289]
3 years ago
12

I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help

. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. I need help. v

Mathematics
2 answers:
dsp733 years ago
5 0

Answer: Its C (-3,-3)

Step-by-step explanation:

Klio2033 [76]3 years ago
3 0

Answer:

the y-intercept is 0

so your answer is B

Step-by-step explanation:

The y-intercept of a line is the value of y where the line crosses the y-axis. In other words, it is the value of y when the value of x is equal to 0.

To find the x-intercept, substitute in 0 for y and solve for x

To find the y-intercept, substitute in 0 for x and solve for y.

Hope this helps :)

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

.

.

.

Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
2 years ago
PLZ HELP I'VE BEEN STUCK FOR A LONG TIME PLZ HELP
ziro4ka [17]

Answer:

c/d = 6

Step-by-step explanation:

Use the second equation.

c - 6d = 0

Add 6d to both sides.

c = 6d

Divide both sides by d.

c/d = 6

7 0
3 years ago
PLEASE HELP!! WILL MARK BRAINLIEST IF RIGHT!!!
denpristay [2]

Answer:

images are:

W'(-5,0)

X'(0,-9)

Y'(-9,-6)

Z'(-6,-2)

Step-by-step explanation:

use formula p(x,y)=p'(y,-x)

4 0
3 years ago
A chameleon is looking for prey. Let positive numbers represent the elevation of prey above the chameleon and negative numbers r
zhuklara [117]

Answer:

(B)

The elevation of the chameleon

Step-by-step explanation:

the fly is above the chameleon, so it's elevation should be represented by a positive number

5 0
3 years ago
I’m confused on this one
lions [1.4K]

Remark: What might be confusing you is the the given expression must add up to 90o. You know this because <B = 90 so the other two angles must be 90o.

Equation

5x - 10 + 6x - 21 = 90 Combine like terms on the left

11x - 31 = 90 Add 31 to both sides.

11x - 31 + 31 = 90 + 31

11x = 121 Divide by 11

x = 121/11 = 11.

Find the value of 6x - 21

6*11 - 21 = 66 - 21= 45

Comment

The central angle for arc AB (which is double ADB = 2*45 =90) is 90. So arc AB = 90

5 0
3 years ago
Read 2 more answers
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