Which quantity could go in the blank to make the equation true?

Mathematics

2 answers:

Luda [366]3 years ago

6 0

The answer is D just subtract the 5 and 2

denpristay [2]3 years ago

4 0

3x because 3x+2x=5x hope this helps

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Let [v1,v2,v3] be a set of nonzero vectors in r^m such that the (transpose of vi)*vj = 0 when i is not equal to j. show that the

babunello [35]

Let $\mathbf V$ be the $m\times3$ matrix whose columns are $\mathbf v_1,\mathbf v_2,\mathbf v_3$ , and let $\mathbf c$ be the vector whose components are the constants $c_1,c_2,c_3$ . Now consider the matrix equation

$\mathbf V\mathbf c=\mathbf 0$

Multiplying both sides by $\mathbf V^\top$ , we have

$\mathbf V^\top(\mathbf V\mathbf c)=(\mathbf V^\top\mathbf V)\mathbf c=\mathbf 0$

More explicitly, we're writing

$\mathbf V=\begin{bmatrix}\mathbf v_1&\mathbf v_2&\mathbf v_3\end{bmatrix}$

Multiply both sides by $\mathbf V^\top$ and the left hand side can be written as

$\mathbf V^\top\mathbf V=\begin{bmatrix}{\mathbf v_1}^\top\\{\mathbf v_2}^\top\\{\mathbf v_3}^\top\end{bmatrix}\begin{bmatrix}\mathbf v_1&\mathbf v_2&\mathbf v_3\end{bmatrix}=\begin{bmatrix}{\mathbf v_1}^\top\mathbf v_1&{\mathbf v_1}^\top\mathbf v_2&{\mathbf v_1}^\top\mathbf v_3\\{\mathbf v_2}^\top\mathbf v_1&{\mathbf v_2}^\top\mathbf v_2&{\mathbf v_2}^\top\mathbf v_3\\{\mathbf v_3}^\top\mathbf v_1&{\mathbf v_3}^\top\mathbf v_2&{\mathbf v_3}^\top\mathbf v_3\end{bmatrix}$

We're told that ${\mathbf v_i}^\top\mathbf v_j=0$ whenever $i\neq j$ , so we're left with

$\mathbf V^\top\mathbf V=\begin{bmatrix}\|\mathbf v_1\|^2&0&0\\0&\|\mathbf v_2\|^2&0\\0&0&\|\mathbf v_3\|^2\end{bmatrix}$

Each of $\mathbf v_1,\mathbf v_2,\mathbf v_3$ are nonzero, which means their norms are nonzero, which necessarily implies that $\mathbf c=0$ , and so the vectors $\mathbf v_1,\mathbf v_2,\mathbf v_3$ must necessarily be linearly independent.

6 0

3 years ago

Yolanda bought 12 pounds of rice for $5 . How many pounds of rice did she get per dollar?

defon

<h3>Answer: 2.4 pounds per dollar</h3>

Explanation:

We can set up the ratio

12 pounds : 5 dollars

Then divide both parts of that ratio by 5 so that the "5 dollars" becomes "1 dollar"