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xxTIMURxx [149]
2 years ago
9

Which table shows the relationship between x and y as a direct variation?

Mathematics
1 answer:
AVprozaik [17]2 years ago
6 0

Answer: 4

Step-by-step explanation: cause they are in order

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Trisha invited 12 friends to her party. Eight of her friends are girls. What is 8 12 in simplest form?
goblinko [34]

Answer:

2/3

Step-by-step explanation:

4 goes into 8 twice and 4 goes into 12 three times therefore it would be 2/3

7 0
3 years ago
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You have 896 grams of a radioactive
Margarita [4]

Every 56 seconds, the radioactive substance is divided in half.

224 / 56 = 4

We need to cut the substance in half 4 times.

896 / 2 = 448

448 / 2 = 224

224 / 2 = 112

112 / 2 = 56

After 224 seconds, there will be 56 grams of the radioactive substance left over

7 0
3 years ago
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PLS HELP ASAP!! WILL MARK BRAINLYIST
son4ous [18]

Answer:

$39,851.25

Step-by-step explanation:

If the sales increase at a rate of 9% per year, this means it will be 109% of the previous year's value since 100% + 9% = 109%

109% in decimal form = 109/100 = 1.09

Therefore, the exponential function is:

y = 20000 \cdot 1.09^x, where x is the number of years

So when x=8,  

y = 20000 \cdot 1.09^8=39851.252...

After 8 years, annual sales = $39,851.25

7 0
2 years ago
Hey! i’ll give brainliest help thanks
goldfiish [28.3K]
A government by people
7 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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