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Simora [160]
2 years ago
9

I need help ASAP please

Mathematics
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer:

B. 20 feet

Step-by-step explanation:

<u>If the triangles are similar that means the ratio of the sides of the triangles are the same.</u>

Sense the left side of bigger triangle is 4 times bigger than the bottom side of the triangle, then the left side of the smaller triangle is 4 times bigger than the bottom side.

5×4=20

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A square is inscribed in a circle . If the area of the square is 9 inch square what is the ratio of the radius of the circle to
OLga [1]

Answer:

  (√2)/2

Step-by-step explanation:

The ratio of the radius of the circle to the side of the inscribed square is the same regardless of the size of the objects.

The radius of the circle is half the length of the diagonal of the square. For simplicity, we can call the side of the square 1, so its diagonal is √(1²+1²) = √2 by the Pythagorean theorem. The radius is half that value, so is (√2)/2. The desired ratio is this value divided by 1.

Scaling up our unit square to one with a side length of 3 inches, we have ...

  radius/side = ((3√2)/2) / 3 = (√2)/2

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(6 - 1) + (3m)i = -12 + 27i
Yanka [14]

Answer:

We want to solve the equation:

(6 - 1) + (3m)i = -12 + 27i

Where m is a complex number.

first, we can rewrite this as:

5 + 3*m*i = -12 + 27*i

3*m*i = -12 - 5 + 27*i

3*m*i = -17 + 27*i

And we can write m as:

m = a + b*i

Replacing that in the above equation we get:

3*(a + b*i)*i = -17 + 27*i

3*a*i + 3*b*i^2 = -17 + 27*i

and we know that i^2 = -1

3*a*i - 3*b = -17 + 27*i

The real part in the left (-3*b) must be equal to the real part in the right (-17)

then:

-3*b = -17

b = -17/-3 = 17/3

And the imaginary part in the left (3*a) must be equal to the imaginary part in the right (27)

then:

3*a = 27

a = 27/3.

Then the value of m is:

m = a + b*i = (27/3)  + (17/3)*i

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3 years ago
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crimeas [40]

Answer:

4

Step-by-step explanation:

RS + ST = RT

=> 3x-8 + x = 2x

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Subtract 2x from both the sides,

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