PLEASE HELP! I REALLY NEED AN ANSWER, I CAN'T FIGURE IT OUT!

Mathematics

1 answer:

uranmaximum [27]2 years ago

8 0

Answer:

$2 \frac{1}{4} - 1 \frac{3}{4} \\ \frac{(2 \times 4) + 1}{4} - \frac{(1 \times 4) + 3}{4} \\ \frac{8 + 1}{4} - \frac{4 + 3}{4} \\ \frac{9}{4} - \frac{7}{4} \\ \frac{9 - 7}{4} \\ \frac{2}{4} \\ \frac{1}{2}$

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Please help ASAP !!!!!

pochemuha

Answer:

(goh) (0) = 4

Step-by-step explanation:

Given that,

g(x) = 2x

h(x) = x² + 4

We need to find the value of (goh) (0).

Firstly we find (goh),

(goh) = g(h(x))

=g(x²+4)

(goh) (0) = 0²+4

Hence, the required answer is 4.

7 0

2 years ago

If f is a scalar field and F, G are vector fields, then f F, F · G, and F × G are defined by the following. (f F)(x, y, z) = f(x

valentina_108 [34]

Answer:

Step-by-step explanation:

Consider curl $(fF)$ where $f$ is a scalar function and F is a vector function

$F=F_{1}i +F_{2}j +F_{3}k$

i j k

$curl(fF) = \frac{\partial}{\partial x}$ $\frac{\partial}{\partial y}$ $\frac{\partial}{\partial z}$

$fF_{1}$ $fF_{2}$ $fF_{3}$

$curl(fF)=i(\frac{\partial}{\partial y}(fF_{3})-\frac{\partial}{\partial z}(fF_{2}))-j(\frac{\partial}{\partial x}(fF_{3})-\frac{\partial}{\partial z}(fF_{1}))+k(\frac{\partial}{\partial x}(fF_{2})-\frac{\partial}{\partial y}(fF_{1}))$

$=i(\frac{\partial}{\partial y}(F_{3})+\frac{\partial}{\partial y}(f)-\frac{\partial}{\partial z}(F_{2})-\frac{\partial}{\partial z}(f))-j(\frac{\partial}{\partial x}(F_{3})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial z}(F_{1})-\frac{\partial}{\partial z}(f))+k(\frac{\partial}{\partial x}(F_{2})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial y}(F_{1})-\frac{\partial}{\partial y}(f))$