If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
Answer:
Your slope is -1
Step-by-step explanation:
Find the change in x and the change in y and put it in change in y over change in x.
Δx = -1 - -2 = 1
Δy = -1 - 0 = -1
Slope = rise over run = Change in y over change in x = Δy/Δx = -1/1
Therefore the slope is -1/1 which is written as just -1
<span>3/4f + 5 = -5
Subtract 5 from both sides
3/4f= -10
Divide both sides by 3/4 so that the only thing remaining on the left side is the variable f.
Final Answer: f= 40/3 or 13 1/3 *Both answers are equivalent to each other.</span>
Y = mx + b
slope(m) = -1
(2,-4)...x = 2 and y = -4
now we sub and find b, the y int
-4 = -1(2) + b
-4 = -2 + b
-4 + 2 = b
-2 = b
y = -x - 2
x + y = -2 <== standard form
