Answer:
0.0069
Step-by-step explanation:
This is a power series problem.
The taylor power series expansion for sin(x) = x - x³/3! + (x^(5))/5! - (x^(7))/7! + (x^(9))/9! .......
Our question says we should use the first 5 terms to find the value of sin(π). Thus;
sin(π) = π - π³/3! + (π^(5))/5! - (π^(7))/7! + (π^(9))/9!
This gives;
π - (π^(3)/6) + (π^(5))/120 - (π^(7))/5040 + (π^(9))/362880 ≈ 0.0069
Answer:

The number of Bactria after 5.8 hours is 12242.
Step-by-step explanation:
The number of bacteria in a refrigerated food product is given by

where, T is the temperature of the food.
When the food is removed from the refrigerator, then the temperature is given by

We need to find the composite function N(T(t)).




where N(T(t)) is the number of bacteria after t hours.
Substitute t=5.8 in the above function.




Therefore, the number of Bactria after 5.8 hours is 12242.
Can u explain it a little more clearly...
(-4)^2-4(1)(5)
16-4(1)(5)
16-4(5)
16-20
-4
The discriminant is negative so there are no real number solutions.
I am pretty sure it’s c because you go up 4 and over 3 to the right so that would be plus 3