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kvasek [131]
2 years ago
14

ASAP please ........​

Mathematics
1 answer:
alukav5142 [94]2 years ago
8 0

Answer:

i think its B but sorry if im wrong

Step-by-step explanation:

<3

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Please help do tmrw
iren2701 [21]

Answer:

One is 3x+2 while the other is 2x-1

Step-by-step explanation:

It is opposite to one another

the one with 3x+2 is opposite to the non given one and the one withb2x-1 is opposite

5 0
2 years ago
Factor completely m^2 - 5m - 14 show your work
BigorU [14]

Answer:

Factor m^2-5m-14

(m-7) (m+2)



5 0
3 years ago
Read 2 more answers
Death Valley headquarters in California is 190 feet below sea level. Badwater, America's lowest point, is 92 feet lower than Dea
olga_2 [115]

Answer: Badwater is 282 feet below the sea level.

Step-by-step explanation:

Given: Death Valley headquarters in California is 190 feet below sea level. Badwater, America's lowest point, is 92 feet lower than Death Valley headquarters.

To find the depth of Badwater we need to add depth of Death Valley headquarters from sea level to the depth of Badwater from Death valley headquarters.

i.e. The Depth of Badwater from sea-level = 190 feet +92 feet

= 282 feet

Hence, Badwater is 282 feet below the sea level.

3 0
3 years ago
What is the kinetic Energy of a 110 kg linebacker rushing towards his football
Leviafan [203]

<u>Answer:</u>

The Kinetic energy of the 110 kg linebacker is 1375 J

<u>Solution:</u>

The kinetic energy of an object is the energy produced by its velocity. Kinetic energy of an object is directly proportional to the mass and the square of the its velocity.

Therefore, the formula for kinetic energy is

KE=\frac{1}{2} \times m v^{2}

Here, The linebacker’s mass m = 110 kg

The linebacker’s velocity v = 5 m/s

So by substituting the values,

The kinetic energy of linebacker is

K E=\left(\frac{1}{2} \times 110 \times 5 \times 5\right) \text { Joules } \\\\ \Rightarrow (\frac{2750}{2}) Joules = 1375 Joules

3 0
2 years ago
I would like to know what is the value of z
Brrunno [24]

From the chord theorem we know that:


\overline{TW}\cdot\overline{UW}=\overline{CW}\cdot\overline{VW}


so:


\overline{TW}\cdot\overline{UW}=\overline{CW}\cdot\overline{VW}\\\\3\cdot\overline{UW}=x\cdot6\\\\3\cdot(\overline{TU}-\overline{TW})=x\cdot6\\\\&#10;3\cdot(x+7-3)=x\cdot6\\\\3\cdot(x+4)=x\cdot6\\\\3x+12=6x\\\\12=6x-3x\\\\3x=12\qquad|\div3\\\\\boxed{x=4}


Answer C.

3 0
3 years ago
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