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3 years ago

Only 6 of the 75 trees in a park are at least 30 feet tall. What percent of the trees are under 30 feet tall?

Mathematics

1 answer:

wariber [46]3 years ago

6 0

Percentage of tress under 30 = 6/75 x 100 = 8%

Answer: 8%

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Andy bought 4.85 meters of cord. The cord cost 98¢ per meter. He also purchased 9.6 meters of copper wire. It cost $1.29 per met

laiz [17]

The correct answer 2.86

3 0

3 years ago

Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?

Nutka1998 [239]

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}$

${\dashrightarrow \sf{Principle = Rs.30000}}$
${\dashrightarrow \sf {Time = 4 \: years}}$
$\dashrightarrow \sf{Rate = 30\%}$
$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}$

$\dashrightarrow{\sf{Simple \: Interest }}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}$

$\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}$

Where

$\dashrightarrow{\sf{S.I = Simple \: Interest }}$
${\dashrightarrow{\sf{P = Principle }}}$
${\dashrightarrow{\sf{ R = Rate }}}$
${\dashrightarrow{\sf{T = Time}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{P \times R \times T}{100}}}}}}$

Substituting the values

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{30000 \times 120}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\dfrac{3600000}{100}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{\cancel{\dfrac{3600000}{100}}}}}}}$

${\quad {: \implies{\sf{ S.I = \bf{Rs.36000}}}}}$

${\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}$

Henceforth,The Simple Interest is Rs.36000..

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!! ASAP!! ITS ALMOST DUE!!

Artyom0805 [142]

Answer:

I'm pretty sure it's the first one. If i'm wrong i am terribly sorry

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

From a circular cylinder of diameter 10 cm and height 12 cm are conical cavity of the same base radius and of the same height is

Nataliya [291]

<h3>Volume of the remaining solid = 628 cm^2</h3>

<h3>Whole surface area = 659.4 cm^2</h3>

Step-by-step explanation:

Now, Given that:-

Diameter (d) = 10 cm

So, Radius (r) = 10/2 = 5cm

Height of the cylinder = 12cm.

$volume \: of \: the \: cylinder \: = \pi {r}^{2} h$

$= > \pi \times {5}^{2} \times 12 {cm}^{3} = 300\pi {cm}^{3}$

Radius of the cone = 5 cm.

Height of the cone = 12 cm.

$slant \: height \: of \: the \: cone \: = \sqrt{ {h}^{2} + \: {r}^{2} }$

$= > \sqrt{ {5}^{2}+{12}^{2} } cm \: = 13cm$

Volume of the cone = 1/3 *πr^2h

$= > \frac{1}{3} \pi \times {5}^{2} \times 12 {cm}^{3} = 100\pi {cm}^{3}$

therefore, the volume of the remaining solid

$= 300\pi {cm}^{3} - 100\pi {cm}^{3} \\ = 200 \times 3.14 {cm}^{3} = 628 {cm}^{3}$

Curved surface of the cylinder =

$2\pi \: rh \: = 2\pi \times 5 \times 12 {cm}^{2} \\ = 120\pi {cm}^{2} .$

$curved \: surface \: of \: the \: cone \: = \pi \: rl \\ = \pi \times 5 \times 13 {cm}^{2} \\ = 65\pi {cm }^{2} \\ area \: of \: (upper)circular \: base \: \\ of \: cylinder \: = \\ = \pi \: {r}^{2} = \pi \times {5}^{2}$

therefore, The whole surface area of the remaining solid

= curved surface area of cylinder + curved surface area of cone + area of (upper) circular base of cylinder

$= 120\pi {cm}^{2} + 65\pi {cm }^{2} + 25 \pi {cm}^{2} \\ = 210 \times 3.14 {cm}^{2} = 659.4 {cm}^{2}$

<h3>Hope it helps you!!</h3>

6 0

2 years ago

Which of the following systems has an infinite number of solutions?

VARVARA [1.3K]

Answer:

C. x+y = 1 and -x-y = -1

Step-by-step explanation:

Remember that if a system of equations has an infinite number of solutions, then the resulting equation from using the first step of the elimination method would have no variables and would be true.

1) Let's try canceling out the equations in option C, x+y =-1 and -x-y =-1. Add the two equations together. (Work shown in attached picture.)

2) All of the terms cancel out with each other, leaving only a true statement of 0 = 0. Thus, option C is the answer.

3 0

3 years ago