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strojnjashka [21]
2 years ago
11

Please hurry show your work please Solve using elimination (IXL Skill ZQV). Show all your work.

Mathematics
1 answer:
Colt1911 [192]2 years ago
3 0

Answer:

x=5, y=-6, or (5, -6)

Step-by-step explanation:

Hi there!
We are given the following system of equations:
6x + 3y =12
-2x-5y=20

And we want to solve it by elimination, where we will add the equations together, clear one of the variables, solve for the other variable, and then use the value of the solved variable to find the value of the first variable, that was cleared earlier

Before we clear a variable, we want the values of the coefficients to have opposite signs; for example, if we wanted to clear x in these equations, we would want the coefficients of x in both equations to be 2 and -2, or 6 and -6

In order to get the coefficients to have opposite signs, we can multiply or divide the equations by any numbers to get to the desired coefficients

For this solution, let's clear x, but you can choose to clear y if you wish; right now, the coefficients of x are 6 and -2

If we divide both sides of the first equation by 3, the equation will become 2x + y = 4, which if we add that to -2x-5y=20, we'll clear x and only have y left

In that case, take 6x + 3y =12 and divide both sides by 3

6x+3y=12

÷3        ÷3

________

2x + y = 4

Now add 2x + y =4 with -2x - 5y = 20; notice how the 2x and the -2x cancel out:

2x + y = 4

-2x-5y=20
________
0x - 4y =24

-4y=24

Divide both sides by -4

y=-6
We now have the value of y
Now we need to find the value of x

We can substitute -6 as y into either one of the equations (6x + 3y = 12 OR -2x - 5y =20) to solve for x

Let's take 6x + 3y = 12 for example
Substitute -6 as y into the equation:
6x + 3(-6) = 12

Multiply

6x - 18 = 12

Add 18 to both sides

6x = 30
Divide both sides by 6

x=5

The solution is x=5, y=-6, or as a coordinate point, (5, -6)
Hope this helps!

Want to see another example of these types of problems? Try this question! brainly.com/question/24785499

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Answer:

(a)The percentage of hatchbacks that run on gasoline.=78%

(b) The percentage of diesel vehicles that are hatchbacks.=21%

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Step-by-step explanation:

This table gives information about vehicles sold at a dealership in a month.

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SUV----------------3----------------7

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(b) The percentage of diesel vehicles that are hatchbacks.

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Percentage of diesel vehicles that are hatchbacks=(5÷24)X100=21%

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Number of Diesel Sedans=12

Percentage of sedan that run on diesel=(12÷27)X100=44%

(f)The percentage of gasoline vehicles that SUVs.

Total Number of Gasoline Vehicles=18+15+3=36

Number of Gasoline SUVs=3

Percentage of SUVs that run on gasoline=(3÷36)X100=8%

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