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attashe74 [19]
2 years ago
5

Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.

Mathematics
1 answer:
34kurt2 years ago
5 0

Answer:

  • Infinitely many solutions

Step-by-step explanation:

First, let's organize the equations of the lines into slope-intercept form.

  • x + 4y = 1
  • => 4y = -x + 1
  • => y = -x/4 + 1/4

And,

  • 2x + 8y = 2
  • => 8y = -2x + 2
  • => y = -2x/8 + 2/8
  • => y = -x/4 + 1/4

Since both the graphs are the same, the two equations have infinitely many solutions.

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HELP MEE!!!
SIZIF [17.4K]

A- none because they are parallel lines

5 0
3 years ago
The locations:
GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

AD = \sqrt{(-2 -6)^2 + (3 -8)^2}

AD = \sqrt{89}

CD = \sqrt{(10 -6)^2 + (2 -8)^2}

CD = \sqrt{52}

AB = \sqrt{(-2 -4)^2 + (3 +6)^2}

AB = \sqrt{117}

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
1 year ago
What is the circumference of a circle 68 yard circle?
kati45 [8]
427.26 yards- I am pretty sure.
7 0
3 years ago
I need to know what’s 67x4
Simora [160]

Answer:

268

Step-by-step explanation:

please give brainliest

3 0
3 years ago
Read 2 more answers
What the answer now question
sergejj [24]

Answer:

69 is your answer

Step-by-step explanation:

Have a wonderful day and good luck on you're test!

3 0
3 years ago
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