To solve this, first subtract 6x from both sides.
That is because there cannot be the same variable on both sides of the equation. The new equation would be:
6x=24
Now divide by both sides of the equation by 6
x=4
Hope this helped! Tell me if you have any more questions!
Answer:
Triangles ABE and CDE are congruent by AAS.
Step-by-step explanation:
AB ≅ DC (Opposite sides of a parallelogram are congruent.
m < AEB = m < DEC (Vertical angles).
m < ABE = m < EDC ( Alternate Interior angles).
So triangles ABE and CDE are congruent by AAS.
The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.
We want angle x, which is opposite the side of length 39.
Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x
or 1521 = 3481 + 1296 - 2(36)(59) cos x
Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x
-3256 = -4248cos x
-3256
Then: cosx = --------------- = 0.766
-4248
Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)
Answer:
It has 5 Faces. The 4 Side Faces are Triangles. The Base is a Square. It has 5 Vertices (corner points)
Step-by-step explanation:
