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3 years ago

7

How many golf balls will fit into a suitcase

1 answer:

Goryan [66]3 years ago

4 0

That depends on the volume of the suitcase. The size of all golf balls is the same. The size of all suitcases is not.

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Mark wants to eat one last cookie from the cookie jar in the jar they are fire truck which of cookies six peanut butter cookies

Kisachek [45]

Answer: about 66.6% that he will not pick a PB one

Step-by-step explanation: Put both of them together and you get 15. 15 divede by 3 is 5. Two 5's is 10, which is about nine, so it would be 2/3 chance of getting an oatmeal cookie, which is the opposite of getting a pb one, 2/3 in a percentage is 66.6%

8 0

3 years ago

Read 2 more answers

Write each sum using summation notation<br> 12 + 22 + 32 + 42 + ⋯ + 10000^2

Murljashka [212]

Answer:

50,00,70,000

Step-by-step explanation:

The given sequence is Arithmetic Progression.

Arithmetic Progression is a sequence in which every two neighbor digits have equal distances.

Here first we will find the number of terms

For finding the nth term, we use formula

aₙ = a + (n - 1) d

where, aₙ = value of nth term

a = First term

n = number of term

d = difference

Now, In given sequence: 12, 22, 32, 42, ⋯ , 100002

a = 12, d = 10, n = ? and aₙ= 100002

∴ 100002 = 12 + (n - 1) × (10)

⇒ 99990 = 10(n - 1)

⇒ n = 10000

Now using the formula of Sum of Arithmetic Sequence,

Sₙ = n÷2[2a + (n - 1)d]

⇒ Sₙ = (10000÷2)[2 × 12 + 9999 × 10]

⇒ Sₙ = 5000 [ 24 + 99990]

⇒ Sₙ = 5000 × 100014 = 50,00,70,000

5 0

3 years ago

How do you solve this problem?

umka21 [38]

The answer to your math question is x=5

7 0

2 years ago

Pls help, its probs gonna get deleted

Paladinen [302]

Sorry it took so long :)

3 0

2 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

3 years ago