If |x-16| is less than or equal to 4 and |y-6| is less than or equal to 2, what is the greatest possible value of x-y?
1 answer:
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Answer:
a=35 given
b=40
c=110
I couldn't complete see c. Please look at the picture to see what I assumed it to be.
Step-by-step explanation:
Hmmm... I guess a and b are not vertical.
We are given b=180-4a and a=35 so b=180-4(35)=180-140=40.
So b=40.
Isosceles triangles always have congruent base angles. So let's call both of the base angles in the bottom triangle x.
That means x+x+40=180.
We need to solve this for x.
Combine like terms:
2x+40=180
Subtract 40 on both sides:
2x=140
Divide both sides by 2:
x=140/2
Simplify:
x=70
So I'm assuming that c and it's adjacent angle are sitting on a straightedge together which means 70+c=180.
70+c=180
Subtract 70 on both sides:
c=180-70
Simplify:
c=110
