I'll assume that's


Please let me know if that's wrong.
These are two lines in point slope form. They'll meet at some x that makes the ys equal.





is the only solution.
Exactly one solution.
We really only had to ensure the lines had two different slopes. Then there's always exactly one solution.
If the lines had the same slope, they're either the same line (coincident) so an infinite number of solutions, all the points on that line, or they're parallel, no solutions.
(B) because 1 litter is equal to .1 dekaliter
A standard number cube has 6 sides....
probability of rolling a 5 is 1/6......probability of not rolling a 5 is 5/6
<span>The y-intercept of is .
Of course, it is 3 less than , the y-intercept of .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.
is the mirror image of stretched along the y-direction.
The y-intercept, the value of for , is</span><span>which is times the y-intercept of .</span><span>Because of the negative factor/mirror-like graph, the intervals where increases are the intervals where decreases, and vice versa.
The end behavior is similarly reversed.
If then .
If then .
If then .
The same goes for the other end, as tends to .
All of the above applies equally to any function, polynomial or not, odd, even, or neither odd not even.
Of course, if polynomial functions are understood to have a non-zero degree, never happens for a polynomial function.</span><span> </span>
Answer:
(x-2)²+(y-4)²=4
Step-by-step explanation: