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4 years ago

Point O is the center of the circle in the diagram. What is m∠BCA ?

Mathematics

1 answer:

netineya [11]4 years ago

7 0

The sum of angle around a point equal 360°
so (BOA) = 360-250=110°
and the sum of angle in the shape CAOB = 360°
so BCA = 360-(110+90+90)= 70°
THE ANSWER IS C.70°

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Tory creates a cell phone app. He wants to distribute it through a company that will pay him $100 plus $0.25 every time the app,

MakcuM [25]

Answer: 1520 downloaded's

Step-by-step explanation:

$0.25 divided by $380 = 1520

1520 x $0.25 = $380

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3 years ago

Two of the vertices of a rectangle are (6,1) and (7,1) . IF the rectangle has a perimeter of 18 units, then what are the coordin

fenix001 [56]

Answer:

(6 , -9) (7, -9)

(6, 11) (7, 11)

Step-by-step explanation:

Given: Two of the vertices of a rectangle are (6,1) and (7,1)

Perimeter= 18 units

To get the value of "x"

The distance between Two point can be calculated as (6-7)=-1

Then x= -1

We can get the value of "y" by using expression for perimeter,

The perimeter P= 2x+2y=18

= 2(-1)+2y= 18

-2+2y=18

2y=18+2

2y= 20

y=10

The "y" coordinate can move up or can move down

y1=( 1-10)=-9

y2=( 1+10)=11

Hence, the two other points are;

(6 , -9) (7, -9)

(6, 11) (7, 11)

3 0

3 years ago

I need help really bad help me pls

olasank [31]

Answer: w= 13

Step-by-step explanation: 8+5 is 13

3 0

2 years ago

Read 2 more answers

Which equation is related to x+23=9x+23=9?. a. x−9=23x-9=23 b.x=923x=923 c.x+9=23x+9=23 d. x=813

atroni [7]

I think it's a although I can't really tell.

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3 years ago

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In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Marizza181 [45]

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

3 0

3 years ago