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2 years ago

Please help asap see the picture down below and answer

Mathematics

1 answer:

mina [271]2 years ago

8 0

-9, because the vertex of x^2 would b zero so for it to move to -9 b would need to be -9

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Combine the like terms to create an equivelant expression -3x-6(-1)

Elza [17]

Answer:

-3x+6

Step-by-step explanation:

-3x-6(-1)

First, multiplying two negatives equals a positive: (-)×(-)=(+). Then,

multiply the numbers -3×+6×1 = -3x+6. Then, you got the answer and the answer is -3x+6

3 0

3 years ago

What is the area of the figure, pls hurry 100 points

valentinak56 [21]

Answer:

<h2>25 1/6 square yards</h2>

Step-by-step explanation:

I am assuming you mean the area of the shaded figure.

So, let's do it this way.

Let's subtract the total area from the unshaded area:

7 1/4 x 6 = 43 1/2

Area of non-shaded = 18 1/3

Area of shaded = 43 1/2 - 18 1/3 = 25 1/6

Hope that helps! :)

-Aphrodite

3 0

3 years ago

Write the equation of a quadratic function who has the vertex of (4,-7)

timama [110]

Given:

The vertex of a quadratic function is (4,-7).

To find:

The equation of the quadratic function.

Solution:

The vertex form of a quadratic function is:

$y=a(x-h)^2+k$ ...(i)

Where a is a constant and (h,k) is vertex.

The vertex is at point (4,-7).

Putting h=4 and k=-7 in (i), we get

$y=a(x-4)^2+(-7)$

$y=a(x-4)^2-7$

The required equation of the quadratic function is $y=a(x-4)^2-7$ where, a is a constant.

Putting a=1, we get

$y=(1)(x-4)^2-7$

$y=(x^2-8x+16)-7$ $[\because (a-b)^2=a^2-2ab+b^2]$

$y=x^2-8x+9$

Therefore, the required quadratic function is $y=x^2-8x+9$ .

6 0

2 years ago

Use substitution to solve the following system of equations. What is the value of y? {3x+2y=12{5x−y=7 A) y = -3B) y = 3C) y = -2

Vlad [161]

Answer

B) y = 3

Step-by-step explanation

Given the system of equations:

$\begin{gathered} 3x+2y=12\text{ \lparen eq. 1\rparen} \\ 5x-y=7\text{ \lparen eq. 2\rparen} \end{gathered}$

Isolating x from equation 1:

$\begin{gathered} 3x+2y-2y=12-2y \\ 3x=12-2y \\ \frac{3x}{3}=\frac{12-2y}{3} \\ x=\frac{12}{3}-\frac{2}{3}y \\ x=4-\frac{2}{3}y\text{ \lparen eq. 3\rparen} \end{gathered}$

Substituting equation 3 into equation 2 and solving for y:

$\begin{gathered} 5(4-\frac{2}{3}y)-y=7 \\ 5\cdot4-5\cdot\frac{2}{3}y-y=7 \\ 20-\frac{10}{3}y-y=7 \\ 20-\frac{13}{3}y=7 \\ 20-\frac{13}{3}y-20=7-20 \\ -\frac{13}{3}y=-13 \\ (-\frac{3}{13})\cdot-\frac{13}{3}y=(-\frac{3}{13})\cdot-13 \\ y=3 \end{gathered}$

6 0

1 year ago

⬆️ ⬆️ Question Please Help ☹

zysi [14]

Answer:

See the Venn diagram attached

Numbers given:

Total: 100
Either a cat of a fish: 70
Cat: 46
Cat and fish: 16

Neither a cat or a fish: 100 - 70 = 30

Fish: 70 - (46 + 16) = 70 - 62 = 8

Required probabilities are:

a) P(neither) = 30/100 = 0.3
b) P(f) = (16 + 8)/100 = 0.24
c) P(f not c) = 8/100 = 0.08

6 0

3 years ago

Please help asap see the picture down below and answer ​

Please help asap see the picture down below and answer