Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
Answer:
1296
Step-by-step explanation:
the y is multiplying by six each time 6*6 = 36
36*6 = 216
216*6 = 1296
2196 = 7776
None of the above. 11^8/11^3 is 11^5 since you will just subtract exponents. The numerical value is 161051
although you should have an option that either is 11^5 or equals 11^5 like 11^15/11^10 for example
5 times 100 = 500
500 divided by 20 = 25
25 containers
