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Inga [223]
2 years ago
13

In a lab experiment, 2000 bacteria are placed in a petri dish. The

Mathematics
1 answer:
Kisachek [45]2 years ago
6 0

Answer:

4261

Step-by-step explanation:

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To illustrate the effects of driving under the influence (DUI) of alcohol, a police officer brought a DUI simulator to a local h
Oksanka [162]

Answer:

a) If we design the experiment on this way we can check if we have an improvement with the method used.

We assume that we have the same individual and we take a value before with the normal impaired condition and the final condition is the normal case.  

b) -0.96-2.306\frac{0.359}{\sqrt{9}}=-1.24  

-0.96+2.306\frac{0.359}{\sqrt{9}}=-0.69

The 95% confidence interval would be given by (-1.24;-0.69)

Step-by-step explanation:

Part a

If we design the experiment on this way we can check if we have an improvement with the method used.

We assume that we have the same individual and we take a value before with the normal impaired condition and the final condition is the normal case.

Part b

For this case first we need to find the differences like this :

Normal, Xi 4.47 4.24 4.58 4.65 4.31 4.80 4.55 5.00 4.79

Impaired, Yi 5.77 5.67 5.51 5.32 5.83 5.49 5.23 5.61 5.6

Let d_i = Normal -Impaired

d_i : -1.3, -1.43, -0.93, -0.67,-1.52, -0.69, -0.68, -0.61, -0.81

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.96

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =0.359

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s_d}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=9-1=8  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that t_{\alpha/2}=2.306  

Now we have everything in order to replace into formula (1):  

-0.96-2.306\frac{0.359}{\sqrt{9}}=-1.24  

-0.96+2.306\frac{0.359}{\sqrt{9}}=-0.69  

So on this case the 95% confidence interval would be given by (-1.24;-0.69)

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