Answer:

Step-by-step explanation:
Eliminating a negative and changing our operation

Rewriting our equation with parts separated

Solving the whole number parts

Solving the fraction parts
![-\frac{5}{6} +\frac{1}{4} =[?]](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%3D%5B%3F%5D)
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12

Combining the whole and fraction parts

[RevyBreeze]
the answer to your question there would be 12
Answer:
First day: 45x +20y = 875
Second day: 25x + 40y = 775
Adult ticket price: $15
Step-by-step explanation:
See paper attached. (:
Gavin earns more because he earns 20 per hour and eva earns 11.5 per hour.
So Gavin earns 8.50 more than eva.
Hope this helps :)
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
Read more about Maximization of Area at; brainly.com/question/13869651
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