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o-na [289]
3 years ago
7

In Jerome's physics class, he had to solve the equation 40 = 12mv2 for m. Each step of his work is shown below.

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

Step-by-step explanation:

I think you mean 1/2 for 12. I will assume so

40 = (1/2) m v^2                Multiply both sides by 2

40*2 = (1/2)*2  *m * v^2    Combine the 2s cancel.

80 =  m * v^2                    Divide by v^2

80/v^2 = m * v^2/v^2       Cancel

80/v^2 = m

Since I don't have the drop down menus, you'll have do the matching.

VLD [36.1K]3 years ago
3 0

the answeer is in the picture this is for egde

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6 0
3 years ago
in a 41-49 right triangle, the hypotenuse is 28.83 centimeters. if cos 41= 0.7547, find the length of the side opposite the 49 a
grigory [225]

Answer:

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3 0
3 years ago
Given that A = (4,3,-4), B = (2,8,-5) and C = (-5,5,-8), find the vector from A to the midpoint of BC.
viktelen [127]
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6 0
3 years ago
Yup, pretty much all of it
hjlf
4 x 6 = 24 , 4 x 2 = 8, 4 x 3 = 12, all you have to do is keep going
6 0
3 years ago
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