The perpendicular bisector of side AB of ∆ABC intersects side BC at point D. Find AB if the perimeter of ∆ABC is with 12 cm larg
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33-23=10. 10+23=33. 23-10=13
the numbers are 23 and 10
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But since you can't plant only a fraction of a tree, you can plant a maximum of 4 trees per row.
Now there are ten rows so...
10×4 = 40
You can plant 40 trees at the maximum.
But since you can't plant only a fraction of a tree, you can plant a maximum of 4 trees per row.
Now there are ten rows so...
10×4 = 40
You can plant 40 trees at the maximum.