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Brums [2.3K]
3 years ago
8

The perpendicular bisector of side AB of ∆ABC intersects side BC at point D. Find AB if the perimeter of ∆ABC is with 12 cm larg

er than the perimeter of ∆ACD.
Mathematics
1 answer:
ELEN [110]3 years ago
3 0
AB+BC+AC-12=AC+CD+AD
AB+BC-12=CD+AD
AB+BD+CD-12=CD+AD=BD
AB+BD-12=0
AB=12cm
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Line segment MN is shown below. If point P(x,y) partitions the line segment
Nina [5.8K]

Answer:

P (-1 , 0)

Step-by-step explanation:

M (-6 , 2)      N (9 , -4)     P (x , y)

horizontal distance of M and N = 9 - (-6) = 15

vertical distance of M and N = 2 - (-4) = 6

1/3 from x coordinate of M (-6): -6 + 15/3 = -1    This is x coordinate of point P

1/3 from y coordinate of M (2): 2 - 6/3 = 0    This is y coordinate of point P

P (x , y)  i.e P (-1 , 0)

check: distance of MP = √(-1 - (-6))² + (0 - 2)² = √29 = 5.385

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MP / PN = 5.385 / 10.77 = 0.5 = 1/2

7 0
3 years ago
Evaluate the expression when x= -7.4 and y= -6.3<br>-7y+2x​
GenaCL600 [577]

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-7(-6.3) + 2(-7.4) = -29.3

5 0
3 years ago
Read 2 more answers
Albert wants to show that tan(theta)sin(theta)+cos(theta)=sec(theta). He writes the following proof:
Nataly_w [17]
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
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</span><span>the next step in this proof
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He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
6 0
3 years ago
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Answer:

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The equation for the line is

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