Answer: y=-6
Step by step explanation:
2y-2=-14
2y=-12 (move the negative 2 to the right)
y= -6 (divide both sides by 2)
Your equation is then y=-6
9514 1404 393
Answer:
domain: (-4, -2) ∪ [-1, 4]
range: (-5, 3)
Step-by-step explanation:
<u>Domain</u>
The domain is the horizontal extent of the graph. Here, it is comprised of two intervals. The left interval is open, as the function is not defined for x-values of -4 or -2. That interval is (-4, -2). The right interval is closed, as the function is defined for both x=-1 and x=4. That interval is [-1, 4]. The domain is the union of these two intervals.
D: (-4, -2) ∪ [-1, 4]
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<u>Range</u>
The range is the vertical extent of the graph. The left portion of the graph has a range from -5 to 3, but neither of those values is included in it. That is, the range is an open interval: (-5, 3).
The right portion of the graph has a range from 1 to 2, including both of those values. This interval is already included in the interval (-5, 3), so only one interval is needed to describe the range:
R: (-5, 3)
Answer:
the domain(s) are 7, 5,-3, and -6.
Step-by-step explanation:
the domain is the x which can repeat. the range is the y which can't repeat.
The radius r used in below equations would equal 2in because it is half the given diameter of 4in.
The volume of the cone would be
The volume of a cylinder with the same dimensions would be
The cylinder is 24 - 8 = 16 cubic inches greater.
<span>The equation of a circle with center C=(h,k) and radius r is:
(x-h)^2+(y-k)^2=r^2
In this case the center is the point C=(a,b)=(h,k)→h=a, k=b, then:
(x-a)^2+(y-b)^2=r^2
We can apply the Pythagorean Theorem to find the distance between any point of the circle P=(x,y) and the Center C=(a,b). This distance must be equal to the radius of the circle:
A^2+B^2=C^2, where A and B are the legs of the triangle and C is the hypothenuse.
In this case, according with the figure: The legs of the triangle are:
A=x-a
B=y-b
And the hypothnuse C=r
Then replacing in the Pythagorean Theorem:
(x-a)^2+(y-b)^2=r^2
Equal to the equation of the circle </span>(x-a)^2+(y-b)^2=r^2
