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3 years ago

This is the graph of f(x). Wha is the value of f(2)

Mathematics

1 answer:

Vanyuwa [196]3 years ago

7 0

Answer: 2

Step-by-step explanation:

They are saying that x equals 2, and the question is what the function is defined at when x = 2

Going to x = 2, the y value is just 2

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Korolek [52]

Answer:

0.80
0.289
0.20
0.711

Step-by-step explanation:

Given:

$P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11$

The rule of total probability states that:

$P(A) = P(A\cap B) + P(A\cap B^{c})$

Compute the individual probabilities as follows:

$P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57$

$P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43$

$P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55$

$P(F^{c})=1-P(F)\\=1-0.55\\=0.45$

Conditional probability of an event A given B is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Compute the value of $P(S|F)$ :

$P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80$

Compute the value of $P(S|F^{c})$

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289$

Compute the value of $P(S^{c}|F)$

$P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20$

Compute the value of $P(S^{c}|F^{c})$

$P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711$

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3 years ago