Question

A student rides a bicycle in a circle at a constant speed.

Answer 1

The acceleration of the student-bicycle system is 5 m/s².

The net force on the student-bicycle system

The net force on the student-bicycle system is calculated as follows;

$F_{net} = F_n - F_f\\\\F_{net} = 500 - 250\\\\F_{net} = 250 \ N$

The mass of the student-bicycle system

$m = \frac{W}{g} \\\\m = \frac{500}{10} \\\\m = 50 \ kg$

The acceleration of the student-bicycle system

$a = \frac{F_{net}}{m} \\\\a = \frac{250 \ N}{50 \ kg} \\\\a = 5 \ m/s^2$

The complete question is below:

A student rides a bicycle in a circle at a constant speed. What is the acceleration of the student-bicycle system?

Learn more about net force here: brainly.com/question/14361879