![\bf ~\hspace{10em}1\le x\le 5~\hspace{5em}\sqrt{x^3+36} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{x^3+36}\implies \sqrt{x^{2+1}6^2}\implies \sqrt{x^2x6^2}\implies \sqrt{(6x)^2x}\implies 6x\sqrt{x} \\\\\\ \stackrel{\textit{x = 4}}{6(4)\sqrt{4}}\implies 24\sqrt{2^2}\implies 24\cdot 2\implies 48](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B10em%7D1%5Cle%20x%5Cle%205~%5Chspace%7B5em%7D%5Csqrt%7Bx%5E3%2B36%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Csqrt%7Bx%5E3%2B36%7D%5Cimplies%20%5Csqrt%7Bx%5E%7B2%2B1%7D6%5E2%7D%5Cimplies%20%5Csqrt%7Bx%5E2x6%5E2%7D%5Cimplies%20%5Csqrt%7B%286x%29%5E2x%7D%5Cimplies%206x%5Csqrt%7Bx%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7B%5Ctextit%7Bx%20%3D%204%7D%7D%7B6%284%29%5Csqrt%7B4%7D%7D%5Cimplies%2024%5Csqrt%7B2%5E2%7D%5Cimplies%2024%5Ccdot%202%5Cimplies%2048)
that's how I read it.... to get some value between 1 and 5, namely 4, to make the expression a rational, well, 48 can be expressed as 48/1.
Answer:
7
Step-by-step explanation:
Or 7/1. the equation is y = mx + b. m is the slope. b is the y intercept. so m (the slope) would be 7. And b (the y intercept) would be -9.
Answer:
y = 5x - 5
Step-by-step explanation:
It appears that the graph intersects the y-axis at (0, -5). This point is the y-intercept of the line.
As we move from (0, -5) to the point (2, 5), x increases by 2 and y increases by 10. Thus, the slope of the line through these two points is
m = rise / run = 10 / 2 = 5.
The slope-intercept form of the equation of a straight line, y = mx + b, becomes y = 5x - 5
C) 1 b =-2. D) 7 f(-2) = 3(-8) - 2. -5 x=6
y. 4(y + 1) = x. If (x, y) is the solution to
the system of equations.
Answer:
straight line, C
Step-by-step explanation:
The graph of a linear function is a straight line. Graphically, where the line crosses the x -axis, is called a zero, or root. Algebraically, a zero is an x value at which the function of x is equal to 0 . Linear functions can have none, one, or infinitely many zeros.
I hope this helps.
