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uranmaximum [27]
2 years ago
12

If the scale factor from shape A to B is 5. What is the scale factor from shape B to A?

Mathematics
1 answer:
OLga [1]2 years ago
6 0

Answer:

1/5

Step-by-step explanation:

You need the opposite of 5/1 which would be 1/5

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Suppose y varies directly as x and y=16 when x=8 find y when x=16
ohaa [14]
You have to multiply them
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3 years ago
Please help I don't understand, please show work thank you
Dennis_Churaev [7]
Sum of angles in a triangle is 180°:
180 - 50 - 62 = 68

Sum of angles in a triangle is 180°:
180 - 80 - 53 = 47

Sum of angles in a triangle is 180° / Vertically opposite:
180 - 68 - 47 = 65°

Answer:  65°
3 0
4 years ago
Read 2 more answers
11 Yesterday 170 guests at a hotel called for room service, and 255 guests did not call for room
-Dominant- [34]

Answer:

The percentage of the guests at this hotel called for room service yesterday is 40%

Step-by-step explanation:

We are given

total number of guests called for room services =170

total number of guests did not called for room services =255

now, we can find total number of guests

Total number of guests =(total number of guests called for room services)+(total number of guests did not called for room services)

so,

total number of guests is

=170+255

=425

now, we can find percentage

percentage of the guests at this hotel called for room service yesterday is

%

So,

The percentage of the guests at this hotel called for room service yesterday is 40%

5 0
3 years ago
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
Find the length of side<br> x to the nearest tenth.
Inessa [10]
The answer is the square root of 18 because of Pythagorean theorem
7 0
3 years ago
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