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Whitepunk [10]
2 years ago
8

Choose the solution(s) of the following system of equations:

Mathematics
1 answer:
Tatiana [17]2 years ago
8 0

Answer: (sqrt(6),0)

Step-by-step explanation:

By substituting all of the choices into the equation, we get that the 2nd answer from top is the only answer

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Dont get it wrong, if its wrong i fail, explain how you got your answer
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Answer: 50.24

Area of a circle is pi times r^2

The r is 1/2 the d

So 8/2 = 4

Pi times 4^2= 50.24

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2) There were 228 roses growing in the back garden. If 50% of the
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15 hours, or B

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6 men - 10

12 men - 5

4 men - 15

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Rules for rational numbers
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Part B
Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is 4.6\ miles

Part B) The length of a straight line between the school and the hospital is 2.1\ miles

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

so

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

so

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and C(4.3,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}

d=\sqrt{(1.7)^{2}+(4.3)^{2}}

d=4.6\ miles

Part B) we have that

The hospital is 3.1 miles west of the fire station

so

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(0,0) and D(1.2,1.7)

substitute

d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}

d=\sqrt{(1.7)^{2}+(1.2)^{2}}

d=2.1\ miles

7 0
3 years ago
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