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3 years ago

What is this equation 6x-4y=18 and -x-6y=7

Mathematics

1 answer:

lidiya [134]3 years ago

3 0

Step-by-step explanation:

here you have answer.....

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The price of a geometrical box was Rs 400 last year. It has increased by 12% this year. What is the price now?

mestny [16]

Answer:

Rs 448

Step-by-step explanation:

400 × 1.12 = 448

this a 12 % increase

6 0

3 years ago

Lauren is given a 12% pay rise. Her new salary is £24,080

svet-max [94.6K]

Answer:

21,500

Step-by-step explanation:

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3 years ago

GET 20 PTS AND BE NAMED BRAINLIEST AND GET A THANK U AND A FOLLOW

insens350 [35]

<h3>Therefore 24 students take a car to school. </h3>

Step-by-step explanation:

Given, Total number of students is 80.

and 30% of the total students take a car to school

30% of 80

$=\frac{30}{100}\times 80$

=24

Therefore 24 students take a car to school.

3 0

3 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago

Hi please help me with my math homework

ladessa [460]

Answer:

$\frac{8}{27}$

hope that helps you

8 0

3 years ago

Read 2 more answers